To prepare 250.0 mL of a 0.0550 mol L-1 NH4Cl(aq) solution, follow these steps:
1. Calculate the amount of NH4Cl needed:
moles = concentration * volume
moles = 0.0550 mol L-1 * 0.2500 L
moles = 0.01375 mol
2. Convert the moles of NH4Cl to grams using its molar mass:
molar mass of NH4Cl = (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (1 * 35.45 g/mol)
molar mass of NH4Cl = 53.49 g/mol
grams = moles * molar mass
grams = 0.01375 mol * 53.49 g/mol
grams = 0.735 g (rounded to three decimal places)
3. Weigh out 0.735 grams of NH4Cl using a balance.
4. Transfer the weighed NH4Cl to a clean and dry 250.0 mL volumetric flask.
5. Add distilled water to the flask gradually, swirling gently to dissolve the NH4Cl. Continue adding water until the flask is filled to the calibration mark (250.0 mL).
6. Mix the solution thoroughly by inverting the flask a few times or stirring with a glass rod.
7. Label the flask with the concentration and compound name: "0.0550 mol L-1 NH4Cl(aq)."
You now have a 250.0 mL solution of 0.0550 mol L-1 NH4Cl(aq). Remember to handle chemicals with care and wear appropriate safety equipment.
describe how you would prepare 250.0 mL of 0.0550 mol L-1 NH4Cl(aq)
1 answer
1 answer