how many grams of NH4Cl are required to prepare 250 mL of .122 M NH4Cl solution?
I set this up using the molarity equation and the part that I was missing is moles. So I divided the 0.122 by .25 L and got .031 mol.
Then I took that and multiplied it by the molar mass of NH4Cl and got it wrong.
How do I do this problem?
1 answer
What you did looks ok to me. 1.72 g?It could be that you rounded the 0.0305 to 0.031 too soon. You are allowed three significant figures so I would use 0.0305 for the moles required.