describe how to prepare 500 ml of a 4.5 m solution of acetic acid from 1000.0 ml of a 14.1 stock solution. describe how a student would be able to make this solution. show all necessary calculations

Answer 1

I will assume you mean M and not m. M stands for molarity and m stands for molality. Also, I will assume that the 14.1 material is M since you did not show any unit.
mL1 x M1 = mL2 x M2
500 mL x 4.5M = mL2 x 14.1M
So mL2 = 500 x 4.5/14.1 = 159.57 mL
Add 159.57 mL of the 14.1 M stock solution (probably you would want to use a buret) to a 500 mL volumetric flask. I would add SOME distilled water to the 500 mL flask (say about 250 mL or so), swirl to mix, add water to the mark on the volumetric flask, stopper, mix thoroughly, label. Done.

Answer 2

Thank you so much!!
The work I did was correct then =}

Answer 3

I don't know about that since you chose not to show your work. If you had I could have checked it faster than working the problem myself.