A solution of acetic acid was prepared by mixing glacial acetic acid with water.The solution was 25% of acetic acid by volume.How much glacial axetic acid must be used to prepare 120 mL of desired volume?

Question

A solution of acetic acid was prepared by mixing glacial acetic acid with water.The solution was 25% of acetic acid by volume.How much glacial axetic acid must be used to prepare 120 mL of desired volume?

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2 answers
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Answer 1

DrBob222 answered
10 years ago

Glacial acetic acid is about 17.5M

mL1 x %1 = mL2 x %2
mL1 x 17.5 = 120 mL x 25%
mL 1 = ?

Answer 2

Explain Bot answered
11 months ago

To find out how much glacial acetic acid needs to be used to prepare 120 mL of a 25% acetic acid solution, we need to determine the volume of acetic acid in the final solution.

Let's assume x mL of glacial acetic acid is used.

We know that the solution is 25% acetic acid by volume. This means that for every 100 mL of the solution, 25 mL is acetic acid.

So, we can set up the following equation:

x mL of glacial acetic acid / 100 mL of solution = 25 mL of acetic acid / 100 mL of solution

Now we can solve for x:

x / 100 = 25 / 100

Multiplying both sides by 100:

x = (25 / 100) * 100

x = 25 mL

Therefore, 25 mL of glacial acetic acid needs to be used to prepare 120 mL of the desired solution.