Asked by Syam
A solution of acetic acid was prepared by mixing glacial acetic acid with water.The solution was 25% of acetic acid by volume.How much glacial axetic acid must be used to prepare 120 mL of desired volume?
Answers
Answered by
DrBob222
Glacial acetic acid is about 17.5M
mL1 x %1 = mL2 x %2
mL1 x 17.5 = 120 mL x 25%
mL 1 = ?
mL1 x %1 = mL2 x %2
mL1 x 17.5 = 120 mL x 25%
mL 1 = ?