Asked by Eric
A solution is 40% acetic acid by mass. The density of this solution is 1.049 g/mL. Calcu- late the mass of pure acetic acid in 120 mL of this solution at 20 C.
Answers
Answered by
DrBob222
40% means 40 g acetic acid/100 g soln.
The density is 1.049; therefore, the volume of 100 g soln is 100/1.049 = 95.328 mL. You want 120 mL of the solution; therefore,
40 x (120 mL/95.328 mL) = ?? g in 120 mL.
To check you answer, convert 120 mL to grams and divide (??g/g)*100 soln = should be 40
The density is 1.049; therefore, the volume of 100 g soln is 100/1.049 = 95.328 mL. You want 120 mL of the solution; therefore,
40 x (120 mL/95.328 mL) = ?? g in 120 mL.
To check you answer, convert 120 mL to grams and divide (??g/g)*100 soln = should be 40
Answered by
Lindsey
Calculate what the mass of 120mL of the solution would be, then take 40% of that calculated mass. The resulting figure is the mass of pure acetic acid in the solution.
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