To determine whether a solution of potassium chloride (KCl) with 25 grams at a temperature of 50 degrees Celsius is supersaturated, unsaturated, or saturated, we need to consider the solubility of KCl at that temperature.
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Solubility of KCl at 50°C: The solubility of KCl in water increases with temperature. At 50 degrees Celsius, the solubility of KCl is approximately 31 grams per 100 milliliters of water.
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Calculation of the solution: To assess whether the solution is saturated, unsaturated, or supersaturated, we need to compare the amount of KCl (25 grams) to its solubility at 50°C.
- If the solution contains less KCl than its solubility limit, it is unsaturated.
- If the solution contains KCl equal to its solubility limit, it is saturated.
- If the solution contains more KCl than its solubility limit (which usually requires careful conditions to achieve), it is supersaturated.
Given that the solubility of KCl at 50°C is about 31 grams per 100 mL, let's analyze the situation:
- 25 grams of KCl is less than the solubility limit of 31 grams in 100 mL of water.
- Therefore, a solution with 25 grams of KCl is unsaturated.
In summary, a solution of KCl with 25 grams at 50 degrees Celsius is unsaturated.