Describe a solution of KCL(potassium chloride) that has 50g of KCL and a temperature of 50 degrees Celcius.

Saturated
Unsaturated
Supersaturated

1 answer

To classify the solution of potassium chloride (KCl) you've described (50 grams of KCl in water at 50 degrees Celsius), we need to consider the solubility of KCl at that temperature.

  1. Solubility of KCl at 50 degrees Celsius: The solubility of KCl in water at 50 degrees Celsius is approximately 37.5 grams of KCl per 100 grams of water. This means that KCl can dissolve up to that amount at the specified temperature.

  2. Classification of the solution:

    • Saturated: A saturated solution contains the maximum amount of solute that can dissolve in a solvent at a given temperature. In this case, if you had around 37.5 grams of KCl in 100 grams of water, the solution would be saturated.
    • Unsaturated: An unsaturated solution contains less solute than the solubility limit. For example, if you had only 20 grams of KCl in the same amount of water, the solution would be unsaturated.
    • Supersaturated: A supersaturated solution contains more solute than can typically dissolve at that temperature, often achieved by dissolving solute at a higher temperature and then allowing it to cool slowly.

In your case, if you have 50 grams of KCl in water at 50 degrees Celsius, the solution is supersaturated because 50 grams exceeds the solubility limit of 37.5 grams of KCl in 100 grams of water at that temperature. This means that there's more solute than can typically be held in solution under normal conditions.

Summary:

  • The solution of 50 grams of KCl at 50 degrees Celsius is supersaturated.