Question

Derive the equation of the line in slope-intercept form. 0,-2 and 3,0

Answer 1

First, let's find the slope of the line using the given points (0, -2) and (3, 0).

Slope (m) = (y2 - y1) / (x2 - x1)
m = (0 - (-2)) / (3 - 0)
m = 2 / 3

Now that we have the slope, we can use one of the points to find the y-intercept (b). Let's use the point (0, -2).

y = mx + b
-2 = (2/3)(0) + b
b = -2

Now, we can write the equation of the line in slope-intercept form:

y = (2/3)x - 2