To derive the equation of a line in slope-intercept form (\(y = mx + b\)), we need to identify the slope (\(m\)) and the y-intercept (\(b\)) from the given options. Let's analyze each of the provided equations:
-
\(y = -3x - 4\)
- This is already in slope-intercept form: \(m = -3\), \(b = -4\).
-
\(y = 3x + 4\)
- This is also in slope-intercept form: \(m = 3\), \(b = 4\).
-
\(3x - y = 4\)
- To convert this to slope-intercept form, solve for \(y\): \[ -y = -3x + 4 \quad \Rightarrow \quad y = 3x - 4 \]
- Now it is in slope-intercept form: \(m = 3\), \(b = -4\).
-
\(y = 3x - 4\)
- This is already in slope-intercept form: \(m = 3\), \(b = -4\).
Summary of the equations:
- \(y = -3x - 4\): Slope = -3, y-intercept = -4
- \(y = 3x + 4\): Slope = 3, y-intercept = 4
- \(3x - y = 4\): Converts to \(y = 3x - 4\): Slope = 3, y-intercept = -4
- \(y = 3x - 4\): Slope = 3, y-intercept = -4
If you have a specific equation you want to derive or analyze further, please let me know!