hypot^2=b^2 + 1^2
or
sqrt2 )^2=b^2+1
b^2=2-1
b=1
Dear Jiskha,
I will appreciate if you can show me step by step how this geometry math question is solved.
Using the Pythagorean Theorem,how do i find the length the unknown side 'b'.
Side 'a' has a measurement of 1...the hypotenuse: a square root of 2.
Your help is appreciated.
1 answer