D = 0.08t^2 - 1.6t + 9
is constant acceleration of +0.08 with an initial location of D = 9 and an initial velocity of -1.6
note
when t = 0, D = 9
if you were into calculus I would say more:)
D = 0.08t^2 - 1.6t + 9
Why does this equation above fits this model: A student stands facing a motion detector. He quickly walks toward the detector, slows down, stops and then slowly walks away from the detector. He speeds up as he gets farther away from the detector.
2 answers
just look at the graph of the parabola.
It starts off at a certain value, which decreases, stop, turns around, and then moves back up with greater speed.
There are other formulas which would fit the model, but the parabola is the simplest.
It starts off at a certain value, which decreases, stop, turns around, and then moves back up with greater speed.
There are other formulas which would fit the model, but the parabola is the simplest.