Asked by Jen
Count iblis helped me solve this in another thread. But I am looking for an easier method. Can anyone help?
What I have is
e^x - 2x = e - 2
Solve for x. (The answer is 0.351)
Thanks.
That is a transcendental equation that has to be solved by iteration. A better approximation to the answer is 0.35139.
I got that by using a hand calculator, trying various numbers between 0.351 and 0.352, and interpolating until e^2 - 2x was equal to e - 2 = .71828.
0.35136 is a better answer, to 5 significant figures
5^(2x+1)=X^x
What I have is
e^x - 2x = e - 2
Solve for x. (The answer is 0.351)
Thanks.
That is a transcendental equation that has to be solved by iteration. A better approximation to the answer is 0.35139.
I got that by using a hand calculator, trying various numbers between 0.351 and 0.352, and interpolating until e^2 - 2x was equal to e - 2 = .71828.
0.35136 is a better answer, to 5 significant figures
5^(2x+1)=X^x
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