Asked by Andrea
Another problem plz help Count Iblis. How do you solve 5/x+2 + 2x/x squared - 4= 3/x-2?
5/x+2 + 2x/x squared - 4= 3/x-2
You write the term:
2x/x squared as 2/x
the equation becomes:
5/x+2 + 2/x - 4= 3/x-2
4/x = 0
This equation has no solutions. It is only satisfied in the limit x ---> infinity.
If you take x to be any nonzero number and multiply both sides by x, you obtain the equation:
4 = 0,
which is always false! So, assuming that there is a solution you arrive at a contradiction, so the assumption that a solution exists must be false.
can I ask you another question? what is the answer to 4= square root sign with x-2 underneath it?
4 = sqrt[x -2] -->
16 = |x - 2| And x >=2 --->
x - 2 = 16 And x - 2 >= 0 -->
x = 18
5/x+2 + 2x/x squared - 4= 3/x-2
You write the term:
2x/x squared as 2/x
the equation becomes:
5/x+2 + 2/x - 4= 3/x-2
4/x = 0
This equation has no solutions. It is only satisfied in the limit x ---> infinity.
If you take x to be any nonzero number and multiply both sides by x, you obtain the equation:
4 = 0,
which is always false! So, assuming that there is a solution you arrive at a contradiction, so the assumption that a solution exists must be false.
can I ask you another question? what is the answer to 4= square root sign with x-2 underneath it?
4 = sqrt[x -2] -->
16 = |x - 2| And x >=2 --->
x - 2 = 16 And x - 2 >= 0 -->
x = 18
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