I don't know how you converted density to mols/cc and 55.85/0.141 is not 7.10 BUT 55.85/7.871 = 7.095 g/cc which rounds to 7.10 g/cc and that is the correct answer.
As for the volume, after reading some of your earlier posts, especially the one about the crystal structure of iron, I wonder if the problem intended for you to go through the unit cell business.
could you please check my work?
what is the volume of one mole of solid iron at 25 degrees c?
1 mol Fe/.141 mol/cm^3 = 7.10 cm^3
(the .141 came from converting the density in to moles)
is that correct?
then the next step in the problem is to find the volume of 1 mol of Fe atoms assuming each atom to be spherical. the atomic radius is 0.126 nm.
so i calculated:
4/3 pi (0.126 nm)^3 = .00838 nm^3
is that correct?
thank you for your help.
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By the way, if you are the same John that posted earlier about the boiling point of 2-propanol, I have posted a response to that at the original post. There are two or three things wrong with the way you did it although the Clausius-Clapeyron equation is the correct way to go.
well i thought that by knowing the cubic structure maybe i could work backwards but it just ended up confusing me even more.
6- chloro- 3- hexene
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