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Could you help me with this?

find the real zeros of
f(x) = x^3-8^2+9x+18(x-8^2+9x+18
I know it must be real simple. I have a block somewhere.
Thanks
I think I understand the Descartes rule of sign change.
This equation has 2 sign changes.
The total amount of real positive zeros could be 3 or 0.
I'm confused with negative real zeros and imaginary zeros
Thanks again
Dee
Dee

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