Ask a New Question
Menu

(cosx - sinx)^2 + (cosx + sinx)^2 = 2

Iam in this step:

2cos^2(x) + 2sin^2(x) = 2

How can I make the equation on the right equal 2

2 answers

oh, please. What is the first and most fundamental trig identity you ever learned?

cos^2 + sin^2 = 1

right? Time for the duhh! and head slap.
Thank You
Similar Questions
  1. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
    1. answers icon 0 answers
  2. Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
    1. answers icon 0 answers
  3. prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
    1. answers icon 0 answers
  4. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
more similar questions