CosA+sinA/CosA-SinA

2 answers

Perhaps you mean
(CosA+SinA)/(CosA-SinA )
?
(CosA+SinA)/(CosA-SinA ) * (CosA+SinA)/(CosA+SinA )
=[ cos^2 A + 2 sin A cos A + sin^2 A] /(cos^2A-sin^2 A)
=(1+ 2 sin A cos A)/ cos 2A
= (1+sin 2A) / cos 2A

or, if you will, sec2A + tan2A

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