draw a triangle with opposite leg=x, hypotenuse=1
adjacent leg = √(1-x^2)
however, doing it algebraically,
let θ=sin^-1 x
x = sinθ
cos^2 θ + sin^2 θ = 1
cos^2 θ + x^2 = 1
cos^2 θ = 1 - x^2
cosθ = √(1-x^2)
cos(sin^-1 x)=sq rt(1-x^2)
prove the identity
1 answer