cos θ = (2√(2)) / (3)
sin θ = - (1/3)
then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?
sin θ = - (1/3)
then what would the triangle look like, the placement of the sides on quadrant 1,2,3, or 4?
1 answer
1 answer
3 answers
1 answer