cos(145) = (10000 - 200b + d^2) / (200d - 2bd)

cos(225) = (200b - 10000 + d^2) / (2bd)
Solve simultaneously

1 answer

To solve the given system of equations simultaneously, we can set the two expressions for cos(145) and cos(225) equal to each other and then solve for the variables:

(10000 - 200b + d^2) / (200d - 2bd) = (200b - 10000 + d^2) / (2bd)

Cross multiplying, we get:

(10000 - 200b + d^2)(2bd) = (200b - 10000 + d^2)(200d - 2bd)

Expanding both sides:

20000bd - 400b^2 + 2bd^2 = 40000d - 400bd + 200b^2 - 200000 + 200d^2 - 200bd

Rearranging the terms:

2bd^2 + 200b^2 + 200bd + 200000 + 400bd + 200000 - 20000bd + 40000d - 200d^2 = 0

Rearranging and simplifying further:

-2bd^2 + 200b^2 + 400bd + 40000d - 200d^2 = -400000

Now we can simplify by dividing everything by 2 to get:

-bd^2 + 100b^2 + 200bd + 20000d - 100d^2 = -200000

We have now extracted a single equation relating b and d. However, there may be multiple solutions to this equation, so it is a non-linear system and may require further analysis or the use of numerical methods to find the exact values of b and d.