I have a problem with
Cu+(aq)+2NH3(aq)⟶Cu(NH3)+2(aq)𝐾f=6.3×1010 M−2
Should that be [Cu(NH3)2]^+
and what are you to use for Ksp CuBr?
Copper(I) ions in aqueous solution react with NH3(aq) according to
Cu+(aq)+2NH3(aq)⟶Cu(NH3)+2(aq)𝐾f=6.3×1010 M−2
Calculate the solubility (in g⋅L−1) of CuBr(s) in 0.22 M of NH3(aq).
3 answers
I think you may have written the product Ok except we can't^+ do superscripts right here.
CuBr(s) ==> Cu^+ + Br^- ........Ksp = ?
Cu^+ + 2NH3 ==> [Cu(NH3)2]^+ Kf = ? and add the two to get
---------------------------------------------------
..........CuBr(s) + 2NH3 ==> [Cu(NH3)2]^+ + Br^- Keq = Ksp*Kf
I..........solid.........0.22..............0.....................0
C........solid.........-2x.................x.....................x
E.........solid.......0.22-x.............x.....................x\
Plug the E line into the expression for Keq = Kf*Ksp and solve for x in mols/L. Convert to g/L.
Post your work if you get stuck.
You have Kf in the problem. I found Ksp CuBr = 6.3E-9 but you should use the value in your tables/charts in your notes/text. My first guess is that you will need to solve the quadratic equation.
CuBr(s) ==> Cu^+ + Br^- ........Ksp = ?
Cu^+ + 2NH3 ==> [Cu(NH3)2]^+ Kf = ? and add the two to get
---------------------------------------------------
..........CuBr(s) + 2NH3 ==> [Cu(NH3)2]^+ + Br^- Keq = Ksp*Kf
I..........solid.........0.22..............0.....................0
C........solid.........-2x.................x.....................x
E.........solid.......0.22-x.............x.....................x\
Plug the E line into the expression for Keq = Kf*Ksp and solve for x in mols/L. Convert to g/L.
Post your work if you get stuck.
You have Kf in the problem. I found Ksp CuBr = 6.3E-9 but you should use the value in your tables/charts in your notes/text. My first guess is that you will need to solve the quadratic equation.
kf= 6.3x10^10
ksp= 6.3x10^-9
so... k=396.9 or 4.0x10^2
so then I got 396.9= x^2/(0.22-2x)^2 and solved it getting 15.39 but this answer is wrong
ksp= 6.3x10^-9
so... k=396.9 or 4.0x10^2
so then I got 396.9= x^2/(0.22-2x)^2 and solved it getting 15.39 but this answer is wrong