HELP!!!!!!!!
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The following answers were posted by visitors named HELP!!!!!!!!.
kf= 6.3x10^10 ksp= 6.3x10^-9 so... k=396.9 or 4.0x10^2 so then I got 396.9= x^2/(0.22-2x)^2 and solved it getting 15.39 but this answer is wrong
5 years ago
The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The change in enthalpy upon reaction of 70.64 g Cu2O(s) is −72.08 kJ . Calculate the work, 𝑤 , and energy change, Δ𝑈rxn , when 70.64...
5 years ago