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Give the formula of each coordination compound. Include square brackets around the coordination complex. Do not include the
1 answer
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The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process.
2Cu2O(s)+O2(g)⟶4CuO(s) The
0 answers
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Copper(I) ions in aqueous solution react with NH3(aq) according to
Cu+(aq)+2NH3(aq)⟶Cu(NH3)+2(aq)𝐾f=6.3×1010 M−2
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Answers (2)
The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The change in enthalpy upon reaction of 70.64 g Cu2O(s) is −72.08 kJ . Calculate the work, 𝑤 , and energy change, Δ𝑈rxn ,
kf= 6.3x10^10 ksp= 6.3x10^-9 so... k=396.9 or 4.0x10^2 so then I got 396.9= x^2/(0.22-2x)^2 and solved it getting 15.39 but this answer is wrong