This is just a pair of cones:
z^2 = 4r^2
If θ is the angle from the z-axis, then the cone is just
since z=2r,
tanθ = 1/2
Convert the rectangular equation to an
equation in (a) cylindrical coordinates and (b)
spherical coordinates.
4(x^2 + y^2) = z^2
1 answer