6sinθ=r-5cosθ
6rsinθ = r^2 - 5rcosθ
6y = x^2+y^2 - 5x
now just rearrange the terms
Convert the following equation from an equation using polar coordinates to an equation using rectangular coordinates: 6sinθ=r-5cosθ
a.) 6y=-5x
b.) x^2-6x+y^2-5y=0
c.) x^2-5x+y^2-6y=0
d.) x^2+6x+y^2+5y=0
e.) x^2+5x+y^2+6y=0
f.) 5y=-6x
1 answer