Convert the

Question

given polar equation to a Cartesian equation.

r^2=4sec(theta)csc(theta)

Answer 1

in your repertoire of relations in this topic you should have:
x = rcosØ and y = rsinØ, and r^2 = x^2 + y^2
then r/x = sec‚ and r/y = cscØ

so let's just substitute
r^2 = (4r/x)(r/y)
r^2 = 4r^2 /(xy)
1 = 4/(xy)
xy = 4