Given angle c, ACB
construct a circle with center C intersecting AC at D and CB at E.
Using D as a center, construct a circle with radius DE so it intersects the circle C at F.
Angle FCA = ACB since they subtend equal arcs.
So, FCB = FCA+ACB = 2*ACB
construct-angle-f-so-that-m-angle-f-equals-2-m-angle-c
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