To determine how many \( 1 \frac{7}{8} \) kilogram books can fit into a box that holds \( 28 \frac{1}{8} \) kilograms, you would divide. Specifically, you need to divide the total weight the box can hold by the weight of each book.
Calculation Steps:
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Convert the mixed numbers to improper fractions:
- \( 28 \frac{1}{8} \) can be converted as follows: \[ 28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8} \]
- \( 1 \frac{7}{8} \) can be converted similarly: \[ 1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8} \]
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Now, divide the total weight by the weight of one book: \[ \frac{225/8}{15/8} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} \]
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Simplifying \( \frac{225}{15} \): \[ \frac{225}{15} = 15 \]
Conclusion:
You will divide to solve this problem, and the box can hold 15 books.
Final Response:
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Will you multiply or divide to solve this problem?
Divide -
How many books will it hold?
15 books
2 answers