Consider the reaction: 3A(g) + B(s) ↔ 5C(s) + 2D(g). In a 5.00 L container, the reactants and products are at equilibrium. There are 0.41 mol A, 0.58 mol B, 1.11 mol C, and 0.46 mol D. What is the equilibrium constant?

Answer 1

0.41 mol A, 0.58 mol B, 1.11 mol C, and 0.46 mol D.
moles/L = M = 0.41/5.00 L = ? for A.
For B M = 0.58/5.00 = ?
For C M = 1.11/5.00 = ?
For D M = 0.46/5.00 = ?
Substitute the M for A, B, C, D into the Keq expression and solve. Post your work if you get stuck.
Keq = (C)^5 * (D)^2/(A)^3 * B

Answer 2

thank you very much this was a big help