No it isn't 22.0 g but I think I know what you did wrong. I think you said that 11.0 g O2 x 2 for the coefficient for H2O gives 22.0 grams. It works that way EXCEPT not with grams. The equations work with moles and not grams.
So mols O2 = g O2/molar mass O2 = 11.0 g/32 = 0.344
Now convert to mols H2O produced this way.
0.344 mols O2 x (2 mols H2O produced/1 mol O2) = 0.344 x 2 = 0.688
Then grams H2O = mols H2O x molar mass H2O = 0.688 mols x 18 g/mol = ? grams H2O
Consider the reaction 2H2 + O2 --> 2H2O
What is the mass of water produced when 11.0 grams of O2 reacts with excess H2?
Is the answer 22.0 grams of H2O? That's what I got
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