f ' (x) = 4x^3 - 144x
= 0 at any local max/min
4x(x^2 - 36) = 0
x = 0 , -6, +6
f(0) = 3
f(6) = -1293
f(-6) = -1293
checking for endpoint of domain
f(-5) = -1172
f(13) = 16396
so absolute min = -1293
absolute max = 16396
looks good,
http://www.wolframalpha.com/input/?i=plot++x%5E4+-+72+x%5E2+%2B+3%2C+-5+≤+x+≤+13
Consider the function f(x) = x^4 - 72 x^2 + 3, -5 less than or equal to x less than or equal to 13. This function has an absolute minimum value equal to and an absolute maximum value to
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