if even (y-axis symmetry), then f(-x) = f(x)
if odd (symmetry about origin), then f(-x) = -f(x)
Clearly this function fails both tests.
Consider the function f(x)=x[(2x+1)^2](x-4), without graphing determine if f(x) has line symmetry about the y axis, point symmetry about the origin or neither. Explain.
1 answer