Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the average slope of the function on this interval.

By the mean value theorem, we know there exists at least one c in the open interval (-4,4) such that f’(c) is equal to this mean slope. For this problem, there are 2 values of c that work. The smaller one and the larger one are?

1 answer

f(-4) = 68
f(4) = 28

average slope = (28-68)/(4+4) = -5

f'(x) = 6x-5
f'(c) = 6c - 5 = -5
c = 0

I only get one value.
Similar Questions
  1. Consider the function f(x) = 1/x on the interval [ 4 , 11 ].(A) Find the average or mean slope of the function on this interval.
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. Consider the functionf(x) = 2 x^3 - 12 x^2 - 30 x+ 10 on the interval [ -6 , 8 ]. Find the average or mean slope of the function
    1. answers icon 0 answers
more similar questions