To make the statement true, we need to determine what operator can be inserted in the placeholder to balance the equation. The statement can be rephrased mathematically as:
\[ \frac{8 \cdot 3 + 2 \cdot 6}{60 \div 5 \cdot 3} = ? \]
Calculating the numerator:
\[ 8 \cdot 3 = 24 \] \[ 2 \cdot 6 = 12 \] \[ 24 + 12 = 36 \]
Now for the denominator:
\[ 60 \div 5 = 12 \] \[ 12 \cdot 3 = 36 \]
Thus, we have:
\[ \frac{36}{36} = 1 \]
Now we check various operators to find which one could replace the placeholder to make the equation true (1):
- Addition (+): \( 36 + 1 = 37 \) (not equal to 1)
- Subtraction (−): \( 36 - 1 = 35 \) (not equal to 1)
- Multiplication (×): \( 36 \times 1 = 36 \) (not equal to 1)
- Division (÷): \( 36 \div 36 = 1 \) (this works)
So the operator that can be inserted to make the statement true is:
Division (÷).
1 answer