To determine which operator can be inserted to make the statement true, we need to evaluate both sides of the equation step by step.
First, let's calculate the left-hand side (LHS):
\[ 8 \cdot 3 + 2 \cdot 6 \] Calculating this: \[ 8 \cdot 3 = 24 \] \[ 2 \cdot 6 = 12 \] So, \[ LHS = 24 + 12 = 36 \]
Now, let's calculate the right-hand side (RHS):
\[ 60 \div 5 \cdot 3 \] Calculating this: \[ 60 \div 5 = 12 \] Then: \[ 12 \cdot 3 = 36 \] So, \[ RHS = 36 \]
Now we have: \[ 36 , _ , 36 \] We need to determine which operator can go in the blank space (underscore).
The operators we can use are:
- = (equals)
- < (less than)
-
(greater than)
- ≠ (not equal)
Since LHS = RHS equals both sides (36 = 36), we can insert the equals sign “=”.
The complete statement would be: \[ 8 \cdot 3 + 2 \cdot 6 = 60 \div 5 \cdot 3 \]
Thus, the operator to insert is "=".