consider the electrolysis of molten AlCl3 what must the current be in amps if you need to obtain 25.0 grams of aluminum in 5.00 min

1 answer

It takes 96,485 coulombs to deposit 1 equivalent weight of Al (27/3 = 9 grams).
Therefore, it will take
96,485 x (25/9) to deposit 25.0 grams = ??

The amperes x sec = coulombs.
You know sec (convert 5 min to seconds) and coulombs, calculate amperes.