Asked by Joe
How many hours are required for the deposition of 15.0 grams of Al from molten AlCl3 by a current of 15.0 amps?
Answers
Answered by
DrBob222
It will require 96,485 coulombs to deposit 27/3 = 9 g Al. Therefore, it will require 96,485 x (15/9) coulombs to deposit 15 g.
1 C = Amp x sec. You know C and amps solve for seconds.
1 C = Amp x sec. You know C and amps solve for seconds.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.