Add the voltages from each corner, potential is a scalar, and does not have direction.
V= k(29.3nC)( 2/(.097*.707))
check that.
Consider a square of side length a = 9.7 cm with charged particles at each of the corners. Three of the particles carry +9.3 nC of charge while the fourth particle carries -9.3 nC. In volts, what is the electric potential at the center of the square?
Hint: Choose the potential to be zero for a position very far from the square.
2 answers
Isn't it just suppose to be 9.3nc instead of 29.3nC?
0 answers