E = h * (c / λ)
energy = Planck's constant * speed of light / wavelength
λ = h * c / E
h = 6.63E-34 J·s
λ = 6.626E-34 * 2.998E8 / 3.211E-19
λ = 6.186E-7 m = 618.6 nm
Consider a sample of excited atoms that lie 3.211 × 10–19 J above the ground state. Determine the emission wavelength (in nanometers) of these atoms.
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