Consider a sample of excited atoms that lie 3.211 × 10–19 J above the ground state. Determine the emission wavelength (in nanometers) of these atoms.

Answer 1

E = h * (c / λ)

energy = Planck's constant * speed of light / wavelength

λ = h * c / E

h = 6.63E-34 J·s

λ = 6.626E-34 * 2.998E8 / 3.211E-19

λ = 6.186E-7 m = 618.6 nm