Consider a sample of excited atoms that lie 3.211 × 10–19 J above the ground state. Determine the emission wavelength (in nanometers) of these atoms.

Answer 1

E = h f

3.2 * 10^-19 = 6.6*10^-34 f

f = .485 * 10^15 Hz

T = 1/f = 2.06 * 10-15 seconds

if c = 3*10^8 m/s

lambda =c T =3*10^8 * 2.06*10^-15

= 6.19 * 10^-7 meters

= 619 * 10^-9 meters

Answer 2

((6.626*10^-34)(3.00*10^8))/(3.332*10^-19)
= 5.966*10^-7
in nanometers it is 596.6 nm