Consider a rectangular swimming pool of depth 2.3 m with a width and length of 13 m. What is the force exerted by the water on one of the sidewalls of the pool?

Answer 1

the average depth is 2.3/2

the weight of water at that depth is the mass of water above, times g, times height..

weight of water at depth 2.3/2 m is
density water*g*volume water
1043kg/m^3*9.8N/kg*2.3m/2*1m^2
= 11753N
that is the average force on the wall