I = V/R = 10.9/10 = 1.09 Amps.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
Consider a battery that has Vt = 12.0 V when it is not connected to a circuit. When a
10.0- resistor is connected with the battery, the potential difference across the battery’s terminals drops to 10.9 V. What is the internal resistance of the battery?
3 answers
I = V/R = 10.9/10 = 1.09 Amps.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
I = V/R = 10.9/10 = 1.09 Amps.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
r = V/I = (12-10.9)/1.09 = 1.0 Ohm.
1 answer