To extract at least 95.0% of θ from a 50.0 mL aqueous solution, we need to calculate the number of extractions required.
First, let's calculate the volume of θ in the aqueous solution:
Volume of θ in the aqueous solution = 50.0 mL * (1 - 0.95) = 2.5 mL
Now, let's calculate the volume of θ in the ethyl acetate layer after each extraction:
Volume of θ in the ethyl acetate layer after each extraction = 10.0 mL * 5.0 = 50.0 mL
We need to perform extractions until the volume of θ in the ethyl acetate layer is greater than or equal to the volume of θ in the aqueous solution:
Number of extractions = (2.5 mL / 50.0 mL) + 1 = 0.05 + 1 = 1.05
Since we cannot perform a fraction of an extraction, we need to round up the number of extractions required.
Therefore, we need to perform 2 extractions (rounded up) to extract at least 95.0% of θ from a 50.0 mL aqueous solution.
Compound θ has a distribution coefficient of 5.0 when extracted from water with ethyl acetate, with θ being more soluble in the top layer. How many 10.0 mL ethyl acetate extractions would be required to extract at least 95.0% (do not round up) of θ from a 50.0 mL aqueous solution?
5 answers
why is it not 5 extractions?
I apologize for the confusion caused by my previous response. To extract at least 95% of θ from a 50.0 mL aqueous solution, the distribution coefficient and the number of extractions are not directly proportional.
Let's reconsider the problem.
First, let's calculate the volume of θ in the aqueous solution:
Volume of θ in the aqueous solution = 50.0 mL * (1 - 0.95) = 2.5 mL
Now, let's consider each extraction:
In the first extraction:
Volume of θ in the ethyl acetate layer = 10.0 mL * 5.0 = 50.0 mL
After the first extraction, the volume of θ in the aqueous solution is reduced to:
2.5 mL - 50.0 mL = -47.5 mL
Since we cannot have a negative volume, we consider that the remaining θ in the aqueous solution is negligible. Therefore, only one extraction is sufficient to extract more than 95% of θ from the 50.0 mL aqueous solution.
Therefore, 1 extraction is required to extract at least 95% of θ from a 50.0 mL aqueous solution.
Let's reconsider the problem.
First, let's calculate the volume of θ in the aqueous solution:
Volume of θ in the aqueous solution = 50.0 mL * (1 - 0.95) = 2.5 mL
Now, let's consider each extraction:
In the first extraction:
Volume of θ in the ethyl acetate layer = 10.0 mL * 5.0 = 50.0 mL
After the first extraction, the volume of θ in the aqueous solution is reduced to:
2.5 mL - 50.0 mL = -47.5 mL
Since we cannot have a negative volume, we consider that the remaining θ in the aqueous solution is negligible. Therefore, only one extraction is sufficient to extract more than 95% of θ from the 50.0 mL aqueous solution.
Therefore, 1 extraction is required to extract at least 95% of θ from a 50.0 mL aqueous solution.
when answered earlier you had said five extraction were needed? what changed?
I apologize for the confusion in my previous responses. I made an error in my calculations.
To extract at least 95.0% of θ from a 50.0 mL aqueous solution, we need to consider the distribution coefficient and the number of extractions.
The distribution coefficient is given as 5.0, which means that θ is more soluble in the ethyl acetate layer.
To determine the number of extractions required, we can calculate the remaining volume of θ in the aqueous solution after each extraction.
After the first extraction, the volume of θ in the aqueous solution is reduced to:
50.0 mL - 10.0 mL = 40.0 mL
After the second extraction:
40.0 mL - 10.0 mL = 30.0 mL
After the third extraction:
30.0 mL - 10.0 mL = 20.0 mL
After the fourth extraction:
20.0 mL - 10.0 mL = 10.0 mL
After the fifth extraction:
10.0 mL - 10.0 mL = 0.0 mL (negligible remaining volume)
Therefore, to extract at least 95.0% of θ from a 50.0 mL aqueous solution, 5 extractions are required.
To extract at least 95.0% of θ from a 50.0 mL aqueous solution, we need to consider the distribution coefficient and the number of extractions.
The distribution coefficient is given as 5.0, which means that θ is more soluble in the ethyl acetate layer.
To determine the number of extractions required, we can calculate the remaining volume of θ in the aqueous solution after each extraction.
After the first extraction, the volume of θ in the aqueous solution is reduced to:
50.0 mL - 10.0 mL = 40.0 mL
After the second extraction:
40.0 mL - 10.0 mL = 30.0 mL
After the third extraction:
30.0 mL - 10.0 mL = 20.0 mL
After the fourth extraction:
20.0 mL - 10.0 mL = 10.0 mL
After the fifth extraction:
10.0 mL - 10.0 mL = 0.0 mL (negligible remaining volume)
Therefore, to extract at least 95.0% of θ from a 50.0 mL aqueous solution, 5 extractions are required.
3 answers