Complete the two reduction half reactions for the cell shown at the right, and show the line notation for the cell by dragging labels to the correct position. (The electrode on the left is the anode, and the one on the right is the cathode.)
They give you 2AgCl(s); Pb(s); AgCl(s); PbCl2(s); 2Ag(s); Ag(s); Cl-(aq)
The AgCl is the cathode and PbCl2 is the anode
They say to put in line segment and i put
Pb(s) | Cl-(aq) | PbCl2(s) || Ag(s) | Cl-(aq) | AgCl(s)
its saying it isn't correct can someone please help me and tell me what I'm doing wrong? thanks
3 answers
pb I pbcl2 I cl- II cl- I agcl I ag
THIS is the answer:
Pb(s) | PbCl2(s) | Cl-(aq) || Cl-(aq) | AgCl(s) | Ag(s)
Pb(s) | PbCl2(s) | Cl-(aq) || Cl-(aq) | AgCl(s) | Ag(s)
The answer is
Pb(s)|PbCl2(s)|Cl-(aq)Cl-(aq)|AgCl(s)|Ag(s)
Pb(s)|PbCl2(s)|Cl-(aq)Cl-(aq)|AgCl(s)|Ag(s)
3 answers