Asked by cassie
What is the reduction half-reaction for the following unbalanced redox equation?
Cr2O7^2– + NH4^+ Cr2O3 + N2
A.Cr2O3--> Cr2O7^2–
B.Cr2O7^2– --> Cr2O3
C.NH4^+ --> N2
D.N2 --> NH4^+
I think this is D...?
Cr2O7^2– + NH4^+ Cr2O3 + N2
A.Cr2O3--> Cr2O7^2–
B.Cr2O7^2– --> Cr2O3
C.NH4^+ --> N2
D.N2 --> NH4^+
I think this is D...?
Answers
Answered by
bobpursley
in D, nitrogen atoms lose electrons, that is oxidation, right?
Answered by
cassie
right
Answered by
bobpursley
So D is not reduction.
Answered by
cassie
A is a reduction
Answered by
cassie
bob for some reason these questions are throwing me off - I need to understand this
Answered by
bobpursley
In a, the Cr in the dichromate ion is 6
in the chromate ion, the Cr is 3, so each Cr must lose three electrons in that reaction. It is an oxidation of the Cr ion.
Look at B CAREFULLY> you need to think these out. Smart girls don't guess.
in the chromate ion, the Cr is 3, so each Cr must lose three electrons in that reaction. It is an oxidation of the Cr ion.
Look at B CAREFULLY> you need to think these out. Smart girls don't guess.
Answered by
bobpursley
Cassie: figure the oxidation state in each ion, on each side, then figure out what change occured: losing or gaining electrons.
Answered by
bobpursley
http://www.shodor.org/unchem/advanced/redox/index.html
Answered by
cassie
I know and I don't want to guess - I want to know it...automatically
Answered by
cassie
thank you for your help
Answered by
why
this didnt help
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