What is the reduction half-reaction for the following unbalanced redox equation?
Cr2O7^2– + NH4^+ Cr2O3 + N2
A.Cr2O3--> Cr2O7^2–
B.Cr2O7^2– --> Cr2O3
C.NH4^+ --> N2
D.N2 --> NH4^+
I think this is D...?
11 answers
in D, nitrogen atoms lose electrons, that is oxidation, right?
right
So D is not reduction.
A is a reduction
bob for some reason these questions are throwing me off - I need to understand this
In a, the Cr in the dichromate ion is 6
in the chromate ion, the Cr is 3, so each Cr must lose three electrons in that reaction. It is an oxidation of the Cr ion.
Look at B CAREFULLY> you need to think these out. Smart girls don't guess.
in the chromate ion, the Cr is 3, so each Cr must lose three electrons in that reaction. It is an oxidation of the Cr ion.
Look at B CAREFULLY> you need to think these out. Smart girls don't guess.
Cassie: figure the oxidation state in each ion, on each side, then figure out what change occured: losing or gaining electrons.
http://www.shodor.org/unchem/advanced/redox/index.html
I know and I don't want to guess - I want to know it...automatically
thank you for your help
this didnt help
1 answer