Complete the table to show how many liters of water will be in each tank after 10, 20, and 30 minutes. You can use the calculator to help you solve. Keep in mind, the number of minutes is represented by the variable t.

Question

Tank A
Liters in Tank A after t minutes: 400+(−3t)
Tank B
Liters in Tank B after t minutes: 180+5t
Minutes Liters in Tank A Liters in Tank B
0 400 180
10
20
30

Answer 1

To complete the table, we need to calculate the amount of water in each tank after 10, 20, and 30 minutes using the given formulas.

For Tank A:

The formula is: \[ \text{Liters in Tank A} = 400 + (-3t) \]

For Tank B:

The formula is: \[ \text{Liters in Tank B} = 180 + 5t \]

Now we can substitute the values of \( t \) for 10, 20, and 30 minutes.

When \( t = 10 \):

• Tank A:
  \[ 400 + (-3 \times 10) = 400 - 30 = 370 \]

• Tank B:
  \[ 180 + 5 \times 10 = 180 + 50 = 230 \]

When \( t = 20 \):

• Tank A:
  \[ 400 + (-3 \times 20) = 400 - 60 = 340 \]

• Tank B:
  \[ 180 + 5 \times 20 = 180 + 100 = 280 \]

When \( t = 30 \):

• Tank A:
  \[ 400 + (-3 \times 30) = 400 - 90 = 310 \]

• Tank B:
  \[ 180 + 5 \times 30 = 180 + 150 = 330 \]

Now we can fill out the table:

| Minutes | Liters in Tank A | Liters in Tank B | |---------|-------------------|-------------------| | 0 | 400 | 180 | | 10 | 370 | 230 | | 20 | 340 | 280 | | 30 | 310 | 330 |

This is the completed table with the calculated values for both tanks after 10, 20, and 30 minutes.