To find the power of the circuit, we need to calculate the current flowing through the circuit and the voltage across each resistor.
We are given:
A = 2A (current flowing through the circuit)
V = 6V (voltage applied across the circuit)
To find the current flowing through each resistor, we can use Ohm's Law:
I = V/R
Let's calculate the current flowing through Resistor 1 (R1):
R1 = A3 - A
I1 = V3/R1
Using Ohm's Law, we can find the voltage across Resistor 1 (V1):
V1 = I1 * R1
Now let's calculate the current flowing through Resistor 2 (R2):
R2 = A4 - R1
I2 = V4/R2
Using Ohm's Law, we can find the voltage across Resistor 2 (V2):
V2 = I2 * R2
Finally, let's calculate the total current flowing through the circuit:
Total current (Itotal) = I1 + I2
Now, let's fill in the table and perform the calculations:
Table:
R (Ω) I (A) V(V)
Total
Resistor 1
Resistor 2
Given:
A = 2A
V = 6V
Calculations:
R1 = A3 - A = 3 - 2 = 1Ω
I1 = V3/R1 = 6/1 = 6A
V1 = I1 * R1 = 6 * 1 = 6V
R2 = A4 - R1 = 4 - 1 = 3Ω
I2 = V4/R2 = 6/3 = 2A
V2 = I2 * R2 = 2 * 3 = 6V
Total current (Itotal) = I1 + I2 = 6A + 2A = 8A
Filling in the table:
R (Ω) I (A) V(V)
Total - -
Resistor 1 1Ω 6V
Resistor 2 3Ω 6V
Now that we have the current and voltage values for each resistor, we can find the power of each resistor and the total power of the circuit.
The power (P) of a resistor can be calculated using the formula:
P = I^2 * R
Calculating the power of Resistor 1:
P1 = I1^2 * R1 = 6^2 * 1 = 36W
Calculating the power of Resistor 2:
P2 = I2^2 * R2 = 2^2 * 3 = 12W
The total power of the circuit is the sum of the powers of the two resistors:
Total power of the circuit = P1 + P2 = 36W + 12W = 48W
Therefore, the power of this circuit is 48W.
Complete the table and show all your calculations. What is power of this circuit.
Circuit Diagram:
-- A -- V --
| -- R1 -- A3 --|
--A4 -- R2--
V3 is connect to R1. V4 is connected to R2.
Table:
R (Ω) I (A) V(V)
Total
Resistor 1
Resistor 2
A = 2A
V = 6V
Show the Steps
9 answers
are you sure these answers are correct?
Apologies for any confusion. Let's correct the calculations and find the correct values.
Given:
A = 2A
V = 6V
Calculations:
R1 = A3 - A = 3 - 2 = 1Ω
I1 = V1/R1 = 6/1 = 6A
V1 = I1 * R1 = 6 * 1 = 6V
R2 = A4 - R1 = 4 - 1 = 3Ω
I2 = V2/R2 = 6/3 = 2A
V2 = I2 * R2 = 2 * 3 = 6V
Total current (Itotal) = I1 = 6A (since the circuit is a series circuit)
Filling in the table:
R (Ω) I (A) V(V)
Total 6A 6V
Resistor 1 1Ω 6V
Resistor 2 3Ω 6V
Now let's recalculate the powers:
Power of Resistor 1:
P1 = I1^2 * R1 = 6^2 * 1 = 36W
Power of Resistor 2:
P2 = I2^2 * R2 = 2^2 * 3 = 12W
Total power of the circuit:
Total power = P1 + P2 = 36W + 12W = 48W
So, the correct power of this circuit is 48W.
Given:
A = 2A
V = 6V
Calculations:
R1 = A3 - A = 3 - 2 = 1Ω
I1 = V1/R1 = 6/1 = 6A
V1 = I1 * R1 = 6 * 1 = 6V
R2 = A4 - R1 = 4 - 1 = 3Ω
I2 = V2/R2 = 6/3 = 2A
V2 = I2 * R2 = 2 * 3 = 6V
Total current (Itotal) = I1 = 6A (since the circuit is a series circuit)
Filling in the table:
R (Ω) I (A) V(V)
Total 6A 6V
Resistor 1 1Ω 6V
Resistor 2 3Ω 6V
Now let's recalculate the powers:
Power of Resistor 1:
P1 = I1^2 * R1 = 6^2 * 1 = 36W
Power of Resistor 2:
P2 = I2^2 * R2 = 2^2 * 3 = 12W
Total power of the circuit:
Total power = P1 + P2 = 36W + 12W = 48W
So, the correct power of this circuit is 48W.
What is the total for R, I and V? Show your work.
To find the total resistance (R total), total current (I total), and total voltage (V total), we need to calculate the sum of the individual resistances, currents, and voltages in the circuit.
Given:
R1 = 1Ω
R2 = 3Ω
I1 = 6A
I2 = 2A
V1 = 6V
V2 = 6V
Calculations:
Total resistance (R total) = R1 + R2 = 1Ω + 3Ω = 4Ω
Total current (I total) = I1 = 6A (since the circuit is a series circuit)
Total voltage (V total) = V1 + V2 = 6V + 6V = 12V
Filling in the table:
R (Ω) I (A) V(V)
Total 4Ω 6A 12V
Resistor 1 1Ω 6A 6V
Resistor 2 3Ω 2A 6V
Therefore, the total resistance is 4Ω, total current is 6A, and total voltage is 12V.
Given:
R1 = 1Ω
R2 = 3Ω
I1 = 6A
I2 = 2A
V1 = 6V
V2 = 6V
Calculations:
Total resistance (R total) = R1 + R2 = 1Ω + 3Ω = 4Ω
Total current (I total) = I1 = 6A (since the circuit is a series circuit)
Total voltage (V total) = V1 + V2 = 6V + 6V = 12V
Filling in the table:
R (Ω) I (A) V(V)
Total 4Ω 6A 12V
Resistor 1 1Ω 6A 6V
Resistor 2 3Ω 2A 6V
Therefore, the total resistance is 4Ω, total current is 6A, and total voltage is 12V.
Are you sure the answer for power is correct?
Apologies for the previous incorrect response. Let's recalculate the power for each resistor and the total power for the circuit.
Given:
R1 = 1Ω
R2 = 3Ω
I1 = 6A
I2 = 2A
V1 = 6V
V2 = 6V
Calculations:
Power of Resistor 1:
P1 = I1^2 * R1 = 6^2 * 1 = 36W
Power of Resistor 2:
P2 = I2^2 * R2 = 2^2 * 3 = 12W
Total power of the circuit:
Total power = P1 + P2 = 36W + 12W = 48W
Therefore, the correct power for this circuit is 48W.
Given:
R1 = 1Ω
R2 = 3Ω
I1 = 6A
I2 = 2A
V1 = 6V
V2 = 6V
Calculations:
Power of Resistor 1:
P1 = I1^2 * R1 = 6^2 * 1 = 36W
Power of Resistor 2:
P2 = I2^2 * R2 = 2^2 * 3 = 12W
Total power of the circuit:
Total power = P1 + P2 = 36W + 12W = 48W
Therefore, the correct power for this circuit is 48W.
What is power of this circuit.
Circuit Diagram:
-- A -- V --
| -- R1 -- A3 --|
--A4 -- R2--
V3 is connect to R1. V4 is connected to R2.
Circuit Diagram:
-- A -- V --
| -- R1 -- A3 --|
--A4 -- R2--
V3 is connect to R1. V4 is connected to R2.
Apologies for the confusion. Let's recalculate the power for the circuit based on the given information.
Given:
R1 = 1Ω
R2 = 3Ω
A = 2A
V = 6V
To find the power of the circuit, we need to calculate the total current flowing through the circuit and the total voltage across it.
Since the circuit is a series circuit, the total current flowing through the circuit is equal to the current at any point in the circuit.
Total current (I total) = A = 2A
To find the total voltage (V total) across the circuit, we can use Ohm's Law:
V total = I total * R total
Since our given values only include the resistances for R1 and R2, we need to calculate the total resistance (R total) first:
R total = R1 + R2 = 1Ω + 3Ω = 4Ω
Now we can find the total voltage (V total):
V total = I total * R total = 2A * 4Ω = 8V
The power (P) of the circuit can then be calculated using the formula:
P = V total * I total
Calculating the power of the circuit:
P = 8V * 2A = 16W
Therefore, the power of this circuit is 16W.
Given:
R1 = 1Ω
R2 = 3Ω
A = 2A
V = 6V
To find the power of the circuit, we need to calculate the total current flowing through the circuit and the total voltage across it.
Since the circuit is a series circuit, the total current flowing through the circuit is equal to the current at any point in the circuit.
Total current (I total) = A = 2A
To find the total voltage (V total) across the circuit, we can use Ohm's Law:
V total = I total * R total
Since our given values only include the resistances for R1 and R2, we need to calculate the total resistance (R total) first:
R total = R1 + R2 = 1Ω + 3Ω = 4Ω
Now we can find the total voltage (V total):
V total = I total * R total = 2A * 4Ω = 8V
The power (P) of the circuit can then be calculated using the formula:
P = V total * I total
Calculating the power of the circuit:
P = 8V * 2A = 16W
Therefore, the power of this circuit is 16W.
3 answers