Question

Complete the table and show all your calculations. Determine the power of the circuit.
Circuit Diagram:
-- A -- V --
| -- R1 -- A3 --|
--A4 -- R2--

V3 is connect to R1. V4 is connected to R2.

Table:
R (Ω) I (A) V(V)
Total
Resistor 1
Resistor 2

A = 2A
V = 6V

Show the Steps

Answer 1

What is the total for R, I and V?

Answer 2

To calculate the power of the circuit, we need to find the values of current (I) and voltage (V) for each component (Total, Resistor 1, Resistor 2).

Given information:
A = 2 A
V = 6 V

First, let's calculate the total resistance (R_total) of the circuit:

Resistance of Resistor 1 (R1): R1 = V / I = 6 V / 2 A = 3 Ω
Resistance of Resistor 2 (R2): R2 = V / I = 6 V / 2 A = 3 Ω

Next, let's calculate the current flowing through the circuit (I_total):

Using Kirchhoff's Current Law (KCL), the current flowing into the junction at A3 must equal the current flowing out of the junction at A4. Therefore, I_total = I1 + I2.

Since Resistor 1 is in series with the power source, the current flowing through Resistor 1 (I1) is equal to the total current (I_total). Therefore, I1 = I_total = 2 A.

Since Resistor 2 is in parallel with the power source, the current flowing through Resistor 2 (I2) can be found using Ohm's Law: I2 = V / R2 = 6 V / 3 Ω = 2 A.

Now, let's calculate the voltage drop across each resistor (V1, V2):

Using Ohm's Law, the voltage drop across Resistor 1 (V1) is equal to the current flowing through it (I1) multiplied by its resistance (R1). Therefore, V1 = I1 * R1 = 2 A * 3 Ω = 6 V.

Similarly, the voltage drop across Resistor 2 (V2) is equal to the current flowing through it (I2) multiplied by its resistance (R2). Therefore, V2 = I2 * R2 = 2 A * 3 Ω = 6 V.

Finally, let's fill in the table:

R (Ω) I (A) V (V)
Total
Resistor 1 2 A 6 V
Resistor 2 2 A 6 V

Since the total current passing through the circuit is 2 A and the total voltage is 6 V, the power (P_total) of the circuit can be calculated using the formula: P_total = I_total * V = 2 A * 6 V = 12 W.

Therefore, the power of the circuit is 12 Watts.

Answer 3

Apologies for the oversight. Let's calculate the values of R, I, and V for the complete circuit:

Resistance of Resistor 1 (R1): 3 Ω
Resistance of Resistor 2 (R2): 3 Ω

Since Resistor 1 and Resistor 2 are in parallel, the total resistance (R_total) can be found using the formula:

1 / R_total = 1 / R1 + 1 / R2

1 / R_total = 1 / 3 Ω + 1 / 3 Ω
1 / R_total = 2 / 3 Ω
R_total = 3 Ω / 2 = 1.5 Ω

Now, let's calculate the total current (I_total) and total voltage (V_total) for the circuit:

Using Ohm's Law, the total current (I_total) can be found by dividing the total voltage (V) by the total resistance (R_total):

I_total = V / R_total = 6 V / 1.5 Ω = 4 A

The total voltage (V_total) is equal to the given voltage of 6 V.

Now, let's fill in the table:

R (Ω) I (A) V (V)
Total 1.5 Ω 4 A 6 V
Resistor 1 3 Ω - -
Resistor 2 3 Ω - -

Please note that I apologize for the mistakes in the previous response.