Complete the following equations. Include names of all reactants and products

A) CH3CH2CHCH - CH2+H2O -->
|
CH3

B) CH3CHC=CCH3 + H2 --->
|
CH3

1 answer

A) H2O would most likely donate the electron pair from oxygen into Carbon-5 as it is carrying a +1 formal charge (not shown in question). CH3CH2CH=CH-CH2(+) + H:O:H (which carries 2 non-bonded electron pairs) The Pi-electrons of the double bond between C-3 and C-4 would shift to C-4 and absorb the Hydrogen from the Nucleophilic water. This would then leave C-3 with a formal +1 charge which would attract another water that would dissociate leaving an Hydroxide on C-3. Yield => CH3CH2CHOHCH2CH2OH => Pentan-1,3-diol.

B. In the illustrated formula, from right to left, Carbons 2,3 & 4 need another Hydrogen. This would then be 2-Pentene (CH3CH=CHCH2CH3). This then could be Hydrogenated at the double bond in a prototypical conversion of an alkene to an alkane in the presence of an appropriate metallic catalyst. The yield in this case is Pentane.