To analyze the equation \( \text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaCl} \):
On the reactants side:
- From \( \text{BaCl}_2 \), there are 2 chlorine atoms.
On the products side:
- From \( 2\text{NaCl} \), there are also 2 chlorine atoms.
Thus, the count of chlorine atoms is:
- Reactants: 2
- Products: 2
The correct choice is: reactants: 2; products: 2.
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