Complete the equation so that it has infinite solutions.
4x + 10 = _x + _
9 answers
4x + 10 = 4x + 10
complete the equation so that it has no solution.
5x + 12 = _x + 9
5x + 12 = _x + 9
5x + 12 ≠ 5x + 9
complete the equation so that it has no solution. -7x - 12 = _x + 12
-7x - 12 = -7x + 12
solve for x to determine if the equation has one, none, or infinite solutions.
6 (2x + 4) - 24 = 12x
6 (2x + 4) - 24 = 12x
To determine if the equation has one, none, or infinite solutions, we first simplify it:
6(2x + 4) - 24 = 12x
12x + 24 - 24 = 12x
12x = 12x
Now, let's solve for x:
12x = 12x
Divide by 12:
x = x
Since x = x, this statement is true for all real numbers. This means that there are infinite solutions to this equation as any value of x makes it true.
6(2x + 4) - 24 = 12x
12x + 24 - 24 = 12x
12x = 12x
Now, let's solve for x:
12x = 12x
Divide by 12:
x = x
Since x = x, this statement is true for all real numbers. This means that there are infinite solutions to this equation as any value of x makes it true.
solve for x to determine if the equation has one, none, or infinite solutions.
9 (x + 1) = 3 (5x + 1) - 12
9 (x + 1) = 3 (5x + 1) - 12
To determine if the equation has one, none, or infinite solutions, we first simplify it:
9(x + 1) = 3(5x + 1) - 12
Expanding both sides gives:
9x + 9 = 15x + 3 - 12
9x + 9 = 15x - 9
Now, let's isolate the variable x by first subtracting 9x from both sides:
9 = 6x - 9
Add 9 to both sides:
18 = 6x
Divide by 6:
x = 3
Therefore, the solution to the equation is x = 3, which means there is only one solution.
9(x + 1) = 3(5x + 1) - 12
Expanding both sides gives:
9x + 9 = 15x + 3 - 12
9x + 9 = 15x - 9
Now, let's isolate the variable x by first subtracting 9x from both sides:
9 = 6x - 9
Add 9 to both sides:
18 = 6x
Divide by 6:
x = 3
Therefore, the solution to the equation is x = 3, which means there is only one solution.